1st Law- A body at rest will remain at rest. A body in motion will remain in motion, with constant velocity, unless acted upon by an unbalanced external force.
-The horse in the above video is following this law; there is no outside (unbalanced) force to act on him so he is traveling at constant velocity.
Inertia- The tendency for an object to travel in a straight path, inertia=mass
-The horse in the above video is an excellent example of inertia, following a straight path and its great mass (about 522 kilograms) making it more prown to do so.
2nd Law- Acceleration=directly proportional to force, Acceleration=inversely proportional to mass
-The horse is moving at _ m/s. If more mass were added to the horse by adding a fat person instead of Katie the horse would slow. If the horse were to work harder and apply more force the horse would become faster.
3rd Law- For every (action) force on one body, there is an equal in magnitude but opposite in direction (reaction) force on another body.
-There is one major force pair actting in this video: the horse hoof and the ground. As the horse applies its "horse force" through its hoof to the ground the ground also applies an equal force, but in an opposite direction. That force in the opposite direction is propelling the horse forward and upward so that it can move.
2) Horse Jumping- Projectile Motion (Jump #2)
Jump #2 X-Position Graph
Jump #2 Y-Position Graph
How Far Did Basil Jump?
constant velocity formula=Vx= ∆x / t
v = ∆x/t
15.44 ft/s = ∆x ft/ 1 s
x = 15.44 ft = 4.71 m
3) Horse Jumping- Momentum/Impulse (Jump #3)
Freebody Diagram of Horse in Motion
Jump #3 X-Position Graph
Jump #3 Y-Position Graph
p=mv, momentum = mass*velocity, p=(522kg)*65.2, p=34034.4 Ns
F=(change in p)/(change in time), F = (0)/(3.3), F = 0
J=F(change)t = (change)p = mvf-mvi, J=0*3.3=0=522(65.2)-522(65.2)
J=Ft
-Due to momentum, it is important to "move with the horse" when you are riding it so that you increase the time that you are in contact with the horse. When that time is increased the force against Katie and the horse decreases making for a smoother ride.
4) Horse Jumping- Work/Energy (Jump #4)
Jump #4 X-Position Graph
Jump #4 Y-Position Graph
Still Frame (used to find angle)
W=Fd, W=mad, W=522*0*(whatever the distance the horse travels: 18m or 5.8m)=0J
Power= Force*velocity 522*0*17.5=0W
Power= Work/time=0/.9=0W
Force*velocity= work/time 0=0
How Much Force Did Basil Exert Against the Ground? Fy = ma Fy = 522*9.8 Fy = 5115.6 N
Fy
FT
Fx
21°
F = 5115.6/sin(21) = 14,274.7 N, 21'
Fx = sq.root(Ft^2 - Fy^2) = sq.root(14274.7^2 - 5115.6^2) = 13326.6 N
5) Master Video- Just Watch__
.....This is the Master Video of all the previous horse jumps stitched together
Here is where the videos are analyzed.
Horse Analysis1...Newton's Law
2...Projectile Motion
3...Momentum-Impulse
4...Work Energy
5...Just watch
1) Horse Jumping - Newton's Laws(Jump #1)
1st Law- A body at rest will remain at rest. A body in motion will remain in motion, with constant velocity, unless acted upon by an unbalanced external force.
-The horse in the above video is following this law; there is no outside (unbalanced) force to act on him so he is traveling at constant velocity.
Inertia- The tendency for an object to travel in a straight path, inertia=mass
-The horse in the above video is an excellent example of inertia, following a straight path and its great mass (about 522 kilograms) making it more prown to do so.
2nd Law- Acceleration=directly proportional to force, Acceleration=inversely proportional to mass
-The horse is moving at _ m/s. If more mass were added to the horse by adding a fat person instead of Katie the horse would slow. If the horse were to work harder and apply more force the horse would become faster.
3rd Law- For every (action) force on one body, there is an equal in magnitude but opposite in direction (reaction) force on another body.
-There is one major force pair actting in this video: the horse hoof and the ground. As the horse applies its "horse force" through its hoof to the ground the ground also applies an equal force, but in an opposite direction. That force in the opposite direction is propelling the horse forward and upward so that it can move.
2) Horse Jumping- Projectile Motion (Jump #2)
How Far Did Basil Jump?
constant velocity formula=Vx= ∆x / t
v = ∆x/t
15.44 ft/s = ∆x ft/ 1 s
x = 15.44 ft = 4.71 m
3) Horse Jumping- Momentum/Impulse (Jump #3)
p=mv, momentum = mass*velocity, p=(522kg)*65.2, p=34034.4 Ns
F=(change in p)/(change in time), F = (0)/(3.3), F = 0
J=F(change)t = (change)p = mvf-mvi, J=0*3.3=0=522(65.2)-522(65.2)
J=Ft
-Due to momentum, it is important to "move with the horse" when you are riding it so that you increase the time that you are in contact with the horse. When that time is increased the force against Katie and the horse decreases making for a smoother ride.
4) Horse Jumping- Work/Energy (Jump #4)
W=Fd, W=mad, W=522*0*(whatever the distance the horse travels: 18m or 5.8m)=0J
Power= Force*velocity 522*0*17.5=0W
Power= Work/time=0/.9=0W
Force*velocity= work/time 0=0
How Much Force Did Basil Exert Against the Ground?
Fy = ma
Fy = 522*9.8
Fy = 5115.6 N
F = 5115.6/sin(21) = 14,274.7 N, 21'
Fx = sq.root(Ft^2 - Fy^2) = sq.root(14274.7^2 - 5115.6^2) = 13326.6 N
5) Master Video- Just Watch__
.....This is the Master Video of all the previous horse jumps stitched together